.MTA1OQ.NzE1OTM: Difference between revisions

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(Created page with "Promiscuous Questions (1.) The perambulator, or surveying wheel, is so contrived as to turn fast twice in the length of a pole or 16 1/2 feet; what then is the Diameter. 2}16....")
 
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Line 29: Line 29:
       1.30103
       1.30103
S. of A 23.35' = 9.60206
S. of A 23.35' = 9.60206
To find AB
Sec. of A 23[degree symbol].35 = 10.03788
                                        AC 20 = 1.30103
          Rad. 90[degree symbol] = 10.00000
                                                    11.30103
                                          40      10.03788
                                    AB 18.33 = 1.26315
                                    BD  21.67
To find the angle CDB
BD  21.67= 1.33586
Rad. 90 =    10.00000
CB    8=      0.90309
                  10.90309
                    1.33586
{unclear] =    9.56723
To find CD
Rad. 90[degree symbol] = 10.00000
BD 21.67 = 1.33586
Sec of D 90[degree symbol].16' = 10.02776
CD 23.1 = 1.36362

Latest revision as of 01:40, 29 November 2020

Promiscuous Questions (1.) The perambulator, or surveying wheel, is so contrived as to turn fast twice in the length of a pole or 16 1/2 feet; what then is the Diameter. 2}16.5

    8.25 circumference of the wheel

3.14159) 8.25000000

              6.28318
              1966820
              1884954
                  818660
                  628318
                  1903420
                  1884954
                      18466

DIameter 2.6261

Ques 2: Two sides of a triangle are respectively 80 and 40 [unclear: Perches?] required the third so that the content may be just an acre. Make 40 [unclear: perches?] the base, & the perpendicular must be [unclear]. Thus: [drawing of traingles in a rectangle with lettered points and numbers along lines]

By Calculation. To find the angle CAB AC20 = 1.30103 Rad. 90[degree symbol] = 10.00000 CB [unclear] = 0.90309

    10.90309
      1.30103

S. of A 23.35' = 9.60206

To find AB Sec. of A 23[degree symbol].35 = 10.03788

                                       AC 20 = 1.30103
          Rad. 90[degree symbol] = 10.00000
                                                    11.30103
                                          40      10.03788
                                   AB 18.33 = 1.26315
                                   BD  21.67

To find the angle CDB BD 21.67= 1.33586 Rad. 90 = 10.00000 CB 8= 0.90309

                  10.90309
                    1.33586

{unclear] = 9.56723


To find CD Rad. 90[degree symbol] = 10.00000 BD 21.67 = 1.33586 Sec of D 90[degree symbol].16' = 10.02776 CD 23.1 = 1.36362