.MTA1OQ.NzE1OTY: Difference between revisions
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(Created page with "Continued 65 Ques.5) The ellipse in Gravesner square measures 840 links the longest way, and 612 the shortest, within the rails: now the wall being 14 inches thick, it is req...") |
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Ques.5) The ellipse in | Ques.5) The ellipse in Grovesnor square measures 840 links the longest way, and 612 the shortest, within the rails: now the wall being 14 inches thick, it is required to find what quantity of ground it encloses, and how much it stands upon? | ||
[ | [calculations] | ||
Ans. It enclose 4 Acres of Roads and 6 perches. | |||
Then 6680.8+4875.04 = 32569167.232 and 32569167.232+.8754 = 25579823.8440128 equal to the square inches in the ellipse.This divided by 144(equal to a square foot) gives the square feet, viz. 177637.6662778 including the wall. Therefore 403.92 + 554.4 = 223933.848 and 223933.248 + .8754 = 175877.1729792 = number of square feet within the wall. | Then 6680.8+4875.04 = 32569167.232 and 32569167.232+.8754 = 25579823.8440128 equal to the square inches in the ellipse.This divided by 144(equal to a square foot) gives the square feet, viz. 177637.6662778 including the wall. Therefore 403.92 + 554.4 = 223933.848 and 223933.248 + .8754 = 175877.1729792 = number of square feet within the wall. | ||
[ | [calculations] | ||
Latest revision as of 04:24, 29 November 2020
Continued 65 Ques.5) The ellipse in Grovesnor square measures 840 links the longest way, and 612 the shortest, within the rails: now the wall being 14 inches thick, it is required to find what quantity of ground it encloses, and how much it stands upon? [calculations] Ans. It enclose 4 Acres of Roads and 6 perches. Then 6680.8+4875.04 = 32569167.232 and 32569167.232+.8754 = 25579823.8440128 equal to the square inches in the ellipse.This divided by 144(equal to a square foot) gives the square feet, viz. 177637.6662778 including the wall. Therefore 403.92 + 554.4 = 223933.848 and 223933.248 + .8754 = 175877.1729792 = number of square feet within the wall. [calculations]