.MTA1OQ.NzE1OTU: Difference between revisions

From Newberry Transcribe
Jump to navigation Jump to search
(Created page with "(Ques. 4) Continued What proportion does the [unclear] of Frand, which contains 100 square poles of 18 feet each bear to the American acre, containing 160 square poles of 16....")
 
imported>CastleCourt
No edit summary
 
Line 1: Line 1:
(Ques. 4)  Continued
(Ques. 4)  Continued
What proportion does the [unclear] of Frand, which contains 100 square poles of 18 feet each bear to the American acre, containing 160 square poles of 16.5 feet each, considering that the length of the French foot is to the American as 16 to 15?  Therefore the [unclear] of Frand, is to the American acre as 36264 is to 43560 Then 36864/43560 reduced to its lowest to term, is = 502/605 Thus [claculations] Therefore the Fr arepent is to the American acre as 502 is to 605.
What proportion does the arpent of France, which contains 100 square poles of 18 feet each bear to the American acre, containing 160 square poles of 16.5 feet each, considering that the length of the French foot is to the American as 16 to 15?  Therefore the arpent of France, is to the American acre as 36864 is to 43560 Then 36864/43560 reduced to its lowest to term, is = 502/605 Thus [calculations] Therefore the Fr arepent is to the American acre as 502 is to 605.
[claculations]
[calculations]

Latest revision as of 04:20, 29 November 2020

(Ques. 4) Continued What proportion does the arpent of France, which contains 100 square poles of 18 feet each bear to the American acre, containing 160 square poles of 16.5 feet each, considering that the length of the French foot is to the American as 16 to 15? Therefore the arpent of France, is to the American acre as 36864 is to 43560 Then 36864/43560 reduced to its lowest to term, is = 502/605 Thus [calculations] Therefore the Fr arepent is to the American acre as 502 is to 605. [calculations]