.MTA1OQ.NzE1OTQ: Difference between revisions
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(Created page with "Continued Or, Arithmetically, Thus: [calculations] Angle CAB = EDF EDF subtracted from 180 is equal to ADC. Then in the triangle ADC, we have the sides AD & DE with their incl...") |
imported>CastleCourt No edit summary |
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| Line 3: | Line 3: | ||
[calculations] | [calculations] | ||
Angle CAB = EDF | Angle CAB = EDF | ||
EDF subtracted from 180 is equal to ADC. Then in the triangle | EDF subtracted from 180 is equal to ADC. Then in the triangle ADE, we have the sides AD & DE with their included angle, to find the side AE | ||
[calculations] | [calculations] | ||
half the sum of EAD & AED | half the sum of EAD & AED | ||
[ | [calculations] | ||
of the 2 unknown angles | |||
Ques. 3d. I want the | Ques. 3d. I want the length of a line by which my gardener may strike out a round orangery that shall contain just one acre. | ||
[ | [calculations] | ||
Ans, 27 3/4 yards | |||
Latest revision as of 04:15, 29 November 2020
Continued Or, Arithmetically, Thus: [calculations] Angle CAB = EDF EDF subtracted from 180 is equal to ADC. Then in the triangle ADE, we have the sides AD & DE with their included angle, to find the side AE [calculations] half the sum of EAD & AED [calculations] of the 2 unknown angles
Ques. 3d. I want the length of a line by which my gardener may strike out a round orangery that shall contain just one acre. [calculations] Ans, 27 3/4 yards