.MTA1OQ.NzE1ODg: Difference between revisions
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Making AL radius | Making AL radius | ||
S.L. 57'..18" = 8. | S.L. 57'..18" = 8.22173 | ||
3985 = 3.60043 | 3985 = 3.60043 | ||
S.A.89".2',,42" 9.99994 | S.A.89".2',,42" 9.99994 | ||
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The distance of the moon from the earth, then, is 239,100 miles or just 60 semidiameters of the earth. The distance of the sun is found in the Same way, whose parallactic angle is 8" 65/100 | The distance of the moon from the earth, then, is 239,100 miles or just 60 semidiameters of the earth. The distance of the sun is found in the Same way, whose parallactic angle is 8" 65/100 | ||
_______________________________________________ | _______________________________________________ | ||
Rule. To find the exact logarith, when there and Seconds in the angle: First, find the log. sine coresponding to the degrees of min (or to the min if there are no degrees) Then find the logarithim sine next under this in the Table, (i.e. coresponding to one min more than the given minutes,) subtract the one from the other, & then say: As 60" are tp | Rule. To find the exact logarith, when there and Seconds in the angle: First, find the log. sine coresponding to the degrees of min (or to the min if there are no degrees) Then find the logarithim sine next under this in the Table, (i.e. coresponding to one min more than the given minutes,) subtract the one from the other, & then say: As 60" are tp the given number of seconds so is that diff. to a number to be added to the log. sine first found. | ||
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Latest revision as of 18:09, 10 September 2020
61
Making AL radius S.L. 57'..18" = 8.22173
3985 = 3.60043
S.A.89".2',,42" 9.99994
13.60037
8.22173
239.100 = 5.37864
The distance of the moon from the earth, then, is 239,100 miles or just 60 semidiameters of the earth. The distance of the sun is found in the Same way, whose parallactic angle is 8" 65/100 _______________________________________________ Rule. To find the exact logarith, when there and Seconds in the angle: First, find the log. sine coresponding to the degrees of min (or to the min if there are no degrees) Then find the logarithim sine next under this in the Table, (i.e. coresponding to one min more than the given minutes,) subtract the one from the other, & then say: As 60" are tp the given number of seconds so is that diff. to a number to be added to the log. sine first found.
Chicago Newberry Library logo stamped in lower right corner